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How to use SohCahToa to find the length of a missing side

February 3, 2013 by Simon 105 Comments

How to use SohCahToa continues, with a video on finding the length of a missing side in a right angle triangle.

Watch the video and try the quick test.

As before you can use SOHCAHTOA to calculate the length of a missing side, although, in this case, you’ll need to:

  • know the length of one side
  • know the size of one of the acute angles

A typical exam question would be along the lines of –

‘Calculate the length of the side marked ‘a.’ Give your answer to 3 significant figures’

length of a missing side

With these type of questions it’s better to have a series of steps:

  • label the side opposite to the angle
  • label the hypotenuse (longest side)
  • label the side adjacent
  • decide which ratio from SohCahToa – in this question we are going to use Soh
  • Once you’ve calculated – check it! – side ‘a’ must be shorter than the hypotenuse. 6.43cm looks about right.
length of a missing side
length of a missing side

Many of the practical applications of this type of maths come from surveying – perhaps finding out the length or height of something when it’s very difficult to measure. Try this example; suppose we want to find out the height of a tower:

length of a missing side

The surveyor can measure the angle, from 5m away, as 32 degrees. Therefore:

height of a tower

.. we can use trigonometry to find out the exact height – in this case the tan rule – Toa:

Height of tower solution

Using a calculator 5 x tan 32 = 3.124. So the height of the tower is 3.125 + the surveyors height of 1.72m:

Total height = 4.844m

Total height = 4.8m (to 2 s.f.)

Here’s some other posts that might be of interest:

How to use SohCahToa to find missing angles in a right angle triangle

How to work out the area of a triangle

The cosine rule

Click here to try theΒ Quick Test SohCahToa

Comments

  1. Heath Duivestein says

    June 18, 2015 at 3:14 pm

    Thanks for a very informative and helpful video about trigonometry
    definitely saved me from an upcoming test

    Reply
  2. christian butterworth says

    June 7, 2015 at 6:04 pm

    Thank you again!!!!! Great help now pumped for the exam tomorrow

    Reply
  3. Salvador Velazquez says

    May 7, 2015 at 2:44 am

    thanks for the video

    Reply
  4. marshallpulham says

    April 12, 2015 at 4:15 am

    Sin being Opp Over Hyp wouldnt you divide the sin40 by the hypoteneuse not
    times 10 man its been a while since ive done this

    Reply
  5. Pat Motley says

    April 2, 2015 at 8:09 pm

    What do you do if the number you are dealing with is above the letter you
    are finding on the equation? Is it multiply of divide?

    Reply
  6. pam2125 says

    March 27, 2015 at 1:39 pm

    Lil different problem..If your treadmill is 6 ft long and is set at an 8%
    grade. How high (in feet) is the front end of the treadmill?
    Thanks

    Reply
  7. Treneice Walker says

    March 22, 2015 at 7:46 pm

    What do you do when its cos instead of sin beacuse my promblems is asking
    me to find the missing angle by using cos πŸ™

    Reply
  8. Lizzy X says

    March 17, 2015 at 7:02 pm

    Thank you so much, I get it now!:)

    Reply
  9. Feras Sabri says

    March 14, 2015 at 7:47 am

    if I have 2 angles on a triangle and they asked me to find length what to
    do >>??

    Reply
  10. Gabriella Gomez says

    March 12, 2015 at 12:55 am

    thank you so much this was extremely helpful

    Reply
  11. jacob lowe says

    February 26, 2015 at 8:09 pm

    Thank you

    Reply
  12. Mikey says

    February 25, 2015 at 4:29 am

    You seem like a very nice man ! Also great video mate. Come on you irons?

    Reply
  13. Srinivasa Yasa says

    February 22, 2015 at 10:47 pm

    this helped a lot thank you

    Reply
  14. ajoksable says

    February 19, 2015 at 6:49 pm

    i dnt really understand this sir thanks

    Reply
  15. KatelynNicole226 says

    February 18, 2015 at 2:44 am

    Thank you SO much I missed a day of class and I used this video to catch my
    self back up!

    Reply
  16. John McGuire says

    February 10, 2015 at 2:14 am

    Very helpful, thank you. Now I’m just looking for when you use Cos or Tan
    to find either the hypotenuse or adjacent. Also solving for when one side
    is labeled “X” or “X+2”. Knowing the difference between adj and Opp and
    knowing when or how to use it.

    Reply
  17. Glerize Anne Mallanao says

    February 5, 2015 at 1:13 pm

    thank i can past my test

    Reply
  18. Eden Harbour says

    February 4, 2015 at 12:25 am

    This was so helpful! Thank you so much!

    Reply
  19. Lawrence Ah-Weng says

    January 18, 2015 at 1:53 pm

    I used this to try and find the hyp in a gcse calculator paper but I got
    12.85575219 which wasn’t bigger than the opp so is it wrong?!

    Reply
  20. Chima Amobi says

    January 17, 2015 at 11:21 pm

    epic stuff you have helped me out alot ;-), but when i checked my
    calculator i got 0.64 is that correct?

    Reply
  21. Epicnerd73 says

    January 2, 2015 at 8:45 pm

    I liked your construction example, it helps people appreciate that this
    stuff is actually useful in real life as a lot of people in my classes
    don’t appreciate maths and think it’s a waste of time πŸ™

    Reply
  22. Alan Sumpton says

    December 27, 2014 at 11:17 pm

    Really helpful, thanks a lot πŸ™‚

    Reply
  23. Sydney T says

    December 9, 2014 at 6:00 pm

    i got 7.45

    Reply
  24. dashaneil henry says

    November 19, 2014 at 4:02 am

    A man walks x km, due north, from point G to point H to point F. The
    distance along a straight line from G to F is 13 km. (a) from the
    information, write a equation in x which satisfies Pythagoras Theorem. Show
    that the equation can be simplified to give X2 +7x -60=0 >>>could yoe solve
    this please

    Reply
  25. Daniel Harris says

    November 17, 2014 at 9:40 am

    Thank you so much you have just clarified the part i was stuck on.

    Reply
  26. hadi farrukh says

    November 5, 2014 at 10:35 pm

    fanatastic explanation. you are an immpecable tutor to say the least.

    Reply
  27. Z3NTR0 says

    November 1, 2014 at 3:30 am

    what if i get a question where it doesn’t state any angles but tells me for
    example, the hypotenuse and the adjacent. because these sorts of questions
    are going to be on my exam

    Reply
  28. Starpilot149 says

    October 16, 2014 at 1:53 am

    This really helps man, thanks.

    Reply
  29. aaron ho says

    October 1, 2014 at 1:20 pm

    very helpful

    Reply
  30. Ashton De Jong says

    September 16, 2014 at 1:06 am

    Thank you so much! I was so confused before.

    Reply
  31. stephen barker says

    August 31, 2014 at 7:17 pm

    whats the best way get a* or a in gcse maths

    Reply
  32. stephen barker says

    August 25, 2014 at 9:01 am

    how do you know if you have to divide or multiply

    Reply
  33. Ryan Callahan says

    July 21, 2014 at 5:13 pm

    Great video, very helpful!

    Reply
  34. stephen barker says

    July 16, 2014 at 8:31 am

    when you work it out is it always 10 x sin 40 or can you do it the other
    way round

    Reply
  35. JΓ₯sΓΈn ß says

    July 11, 2014 at 10:48 am

    I posted a question on one of your other videos. Building things, I usually
    know two desired angles and either O or A. Hardly ever (if ever) known the
    Hypotenuse as it’s normally the value I’m trying to find. Usually know
    angle a, b, and length O or A. Can you tell me what I need to remember for
    this? ie. I have a support that connects at 1800mm high, set out at an
    angle of 15ΒΊ from vertical. So how far out will it be when it reaches the
    floor? a=15 b=90 c=75 O=1800 A=? H=?

    Reply
  36. JΓ₯sΓΈn ß says

    July 11, 2014 at 10:32 am

    I’m trying to find H and A. O=1800mm The building roof example is good –
    but when building most things, you’re less likely to know the H and more
    likely to know the O value (in height) or the A. So using the H as a known
    length seems unlikely because it’s usually the one you can’t reach. Can you
    show this again with the A or O value known?

    Reply
  37. Naif Sayyaf says

    July 9, 2014 at 3:38 pm

    Thank you for this. <3

    Reply
  38. David Johnson says

    July 3, 2014 at 12:07 pm

    sir is it possible that only the opposite side is given with an angle of 90
    deg.?

    Reply
  39. Thomas Russell says

    June 25, 2014 at 3:55 pm

    Actually helped me a lot with GCSE mock exam … Thanks! πŸ™‚

    Reply
  40. drumman Murchie says

    June 12, 2014 at 5:31 pm

    getting stoned on maths wrap

    Reply
  41. Lori Zaitz says

    June 6, 2014 at 2:36 am

    (I’m using my moms youtube right now) omg thank youuuuu! your video saved
    my math final grade! and just to let you know, there is an extremely high
    pitched feedback your mike gets when you talk, I just thought you should
    know. Thank youuuuu!!

    Reply
  42. Thomas Butt says

    May 29, 2014 at 2:20 pm

    Thankyou so much πŸ™‚

    Reply
  43. second gom says

    April 26, 2014 at 8:39 pm

    nice beginning
    πŸ™‚

    Reply
  44. Storm Low says

    April 22, 2014 at 10:24 pm

    Great video!

    Reply
  45. 70carlton says

    March 31, 2014 at 11:35 pm

    Thank you so much Simon very helpful.

    Reply
  46. Diztriction Tableflippa says

    March 20, 2014 at 2:14 pm

    Thank you, helped me!

    Reply
  47. John Hereford says

    March 13, 2014 at 3:04 am

    *students

    Reply
  48. John Hereford says

    March 13, 2014 at 3:04 am

    do you want a job?
    – De La Salle High School

    Reply
  49. arjun Sidhu says

    March 13, 2014 at 2:11 am

    thanks for the help but another question i am confused with. it is that i
    have 2 lengths of 14 cm and 5cm and i have to find the length of the other
    side of the right triangle

    Reply
  50. GeorgePosts says

    March 4, 2014 at 8:27 pm

    Thanks Simon

    Reply
  51. Melissa Saintlot says

    March 3, 2014 at 11:06 pm

    its hypotenuse

    Reply
  52. cheryl robley says

    March 2, 2014 at 11:21 am

    excellent tutorial, thank you I seem to have cracked sin.. however when I
    need the adjacent and have an opp of 3.1cm and an angle of 25.6 degree and
    use TAN I keep getting 1.485 which doesn’t seem a reasonable length, id
    have guessed more like 6cm?? any ideas where Im going wrong?! could it be
    because adj is the denominator not the numerator like when you do sin?
    thank you very much hope my question makes sense!

    Reply
  53. Big Papi says

    February 26, 2014 at 9:50 pm

    thank you so much!

    Reply
  54. jmitsch44827 says

    February 25, 2014 at 4:14 am

    Good explanation, bad audio. Please fix.

    Reply
  55. dayal manger says

    February 19, 2014 at 1:08 pm

    thanks really helped alot

    Reply
  56. Sharyaar Bhatti says

    January 27, 2014 at 12:17 am

    thank you soo much

    Reply
  57. LazymonkeyIndustries says

    January 14, 2014 at 4:09 am

    Thank you very much for this tutorial sir . It’s very helpful especially
    for my upcoming finals πŸ˜›

    Reply
  58. Steve Ballmer says

    January 10, 2014 at 7:43 am

    Great video man πŸ˜›

    keep it up!

    Reply
  59. AM moses says

    December 31, 2013 at 12:03 pm

    Thank u so much!!! U saved me!!!!!

    Reply
  60. Andy Nguyen says

    December 18, 2013 at 12:58 am

    Thank you for your great explanation. This really helped me out a lot!

    Reply
  61. Simon Deacon says

    December 8, 2013 at 10:41 am

    Please like and leave a comment!

    Visit https://www.3minutemaths.co.uk for real maths, tips and techniques.

    Reply
  62. zv3000 says

    November 29, 2013 at 9:15 am

    Hi got a question probably a bit impossible to work out but what if the
    information you have is just the adj and opp besides obviously the 90* ?
    imagine the adj is 53.34 cm and the opp is 10.16 ?

    Reply
  63. Charlie Parker says

    November 15, 2013 at 6:35 pm

    what formula should I do if its given me the angle and the opposite instead
    off the hypotenuse ??

    Reply
  64. Osvaldo D says

    November 15, 2013 at 12:12 am

    Thanks, wouldn’t have done my math project without you :-).

    Reply
  65. john hanley says

    November 12, 2013 at 8:09 pm

    thanks again

    Reply
  66. JamesTheBaker says

    November 7, 2013 at 9:29 pm

    Thank you so much, this was the only area of trig that I wasn’t too sure
    about, even though I did know how to do non-right angled trig

    Reply
  67. Simon Deacon says

    November 4, 2013 at 10:09 pm

    That’s great – thanks for letting me know πŸ™‚

    Reply
  68. Dana Perry says

    November 4, 2013 at 6:26 pm

    I struggled so much with this but you helped me so thank you πŸ™‚

    Reply
  69. Simon Deacon says

    November 4, 2013 at 11:09 am

    Glad to help πŸ™‚

    Reply
  70. Simon Deacon says

    November 4, 2013 at 11:09 am

    Keep working through questions and you’ll be fine. All best S

    Reply
  71. Nezerrath .Gaming says

    November 4, 2013 at 3:12 am

    oh my god the complication but i’m gonna try my best. thank you πŸ™‚

    Reply
  72. dracoclash says

    November 4, 2013 at 2:52 am

    (T-T) thank you so much!

    Reply
  73. Simon Deacon says

    October 28, 2013 at 9:14 pm

    Hi – I think that your calculator is set to degrees rather than radians. (Radians are a different way of measuring an angle and some calculators will allow you to work with either). All best S

    Reply
  74. Simon Deacon says

    October 27, 2013 at 11:59 pm

    Please post, pin, tweet, like or subscribe!

    Reply
  75. Simon Deacon says

    October 27, 2013 at 11:57 pm

    Please post, pin, tweet, like or subscribe!

    Reply
  76. buehlerbri says

    October 26, 2013 at 1:05 am

    I did 10 times sin(40) and I got 7.45 what am I doing wrong

    Reply
  77. Josie Prada says

    October 25, 2013 at 5:48 pm

    such great help ! πŸ™‚

    Reply
  78. Simon Deacon says

    October 6, 2013 at 10:03 pm

    Hi yes Cah would work fine if you had the hypotenuse and the angle …make sure it’s the one adjacent to the adjacent side you are working out. (Hope that makes sense :-).

    All best

    S

    Reply
  79. 23FlukeShot says

    October 6, 2013 at 4:47 pm

    if im given a right angle triangle which asks me to find the missing side in my question the hypotenuse do i use the same method that you did except with cosine in this case?

    Reply
  80. Ian Long says

    September 21, 2013 at 8:30 pm

    love your tutorials, would be really good if you could write a bit bigger for the eejits like me that can’t see that well though. Ta.

    Reply
  81. Simon Deacon says

    September 8, 2013 at 10:01 pm

    Hi – thanks for the question.

    The way SohCahToa works is with the relationship between the angle and the sides. The problem is the opposite and adjacent will change depending upon which angle you’re using. With these sorts of problems it’s probably better to label what you know, then work out if they are opp, adj or hyp, and then go from there.

    I hope this helps.

    All best

    S

    Reply
  82. billybobdog5 says

    September 8, 2013 at 9:22 pm

    why did you use sin 40? why not sin 50? that’s the only thing confusing me

    Reply
  83. John Rivoski says

    September 5, 2013 at 3:49 am

    Thk You SimonDeacon

    Reply
  84. John Rivoski says

    September 5, 2013 at 3:49 am

    th

    Reply
  85. Simon Deacon says

    August 12, 2013 at 1:26 pm

    Hi Zain – you’ll need to know either the length of an adjacent side or the angle to use SohCahToa. If you send me the question (through MathsWrap if easier) I’ll will be happy to help πŸ™‚ All best S

    Reply
  86. zain ali says

    August 12, 2013 at 12:07 am

    what if the hyp is 100 ??

    Reply
  87. Simon Deacon says

    August 2, 2013 at 5:57 pm

    Hi – sounds like you might need to use Area = 1/2abSinC. Use this to find the length of b although you’ll need to change the equation around a little bit.

    I haven’t got a video for this but there’s quite a few on YouTube.

    I hope this helps.

    Best

    S

    Reply
  88. Alfred Chan says

    August 2, 2013 at 4:57 pm

    If im given one angle, one side and the area, how to do i find the rest? (its a scalene triangle)

    Reply
  89. Katrina Brown says

    July 29, 2013 at 11:18 pm

    Thanks you helped a lot:)

    Reply
  90. Simon Deacon says

    June 19, 2013 at 12:48 pm

    Hi – yes, you need to use the inverse on a calculator to find angles.

    Reply
  91. marco s says

    June 19, 2013 at 12:48 am

    do you only inversese sin cos or tan when your finding the angle inside?

    Reply
  92. Libaan Ahmed says

    June 6, 2013 at 5:19 pm

    Thanks so much.

    Reply
  93. Simon Deacon says

    May 9, 2013 at 11:51 am

    Hi Russell – yes, the concept is still the same. You need to know one angle and one side to find another length … sometimes there’s a bit of calculation first to get all the info you need.

    Reply
  94. Russell Siete says

    May 8, 2013 at 7:16 pm

    Denominator / Numerator Sorry flip in words lol.

    Reply
  95. Russell Siete says

    May 8, 2013 at 7:15 pm

    You only multiply the Numerator. But say if I don’t have my Hypo, but rather the Adjacent? Is the the concept still the same? Probably, but what do I do if I have Denominator? Dividing is probably my choice…which I have a difficulty on how to do that. lol

    Reply
  96. john zitro says

    May 3, 2013 at 8:33 pm

    this one i get the formula and the calculation..

    Reply
  97. Simon Deacon says

    April 16, 2013 at 12:08 pm

    Great – thanks for letting me know πŸ™‚

    Reply
  98. Jamie Morgan says

    April 15, 2013 at 8:50 pm

    Cheers mate really helped πŸ™‚

    Reply
  99. Ismael Djibrilla says

    April 14, 2013 at 6:26 am

    thank you so much πŸ™‚

    Reply
  100. Ismael Djibrilla says

    April 14, 2013 at 6:17 am

    thank you so much πŸ™‚

    Reply
  101. Bridget Canavan says

    March 17, 2013 at 5:45 am

    Thanks this is a really helpful video!!! I get it now!
    πŸ™‚

    Reply
  102. Simon Deacon says

    March 1, 2013 at 11:33 am

    That’s great – glad it helped and thanks for letting me know πŸ™‚

    Reply
  103. Marco Deleon says

    March 1, 2013 at 4:47 am

    Really helpful video!!!!!

    Reply
  104. XDinaChowX says

    February 7, 2013 at 7:42 pm

    OMG this was soooooooooooooo helpful! I’m found GCSE maths and I had no idea how to do this trigonometry SOHCAHTOA thing! This video really really really helped! Thanks so much!! :

    Reply
  105. Simon Deacon says

    February 2, 2013 at 9:46 pm

    Hi – latest video – please let me know what you think.. Thanks!

    Reply

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